Answer:
In 0.7 liters (700 ml) there are 122, 85 grams of NaCl
Explanation:
We calculate the weight of 1 mol of NaCl:
Weight 1 mol NaCl= Weight Na + Weight Cl= 23+35,5 g= 58,5g/mol
1 mol NaCl-------58,5 g
3mol NaCl -------x= (3mol NaClx58,5 g)/1 mol= 175, 5 g
3M (175,5 g in this case)---> 3 moles in 1 L of solution
1 L-----175,5 g NaCl
0,7L--x= (0,7Lx175,5 g NaCl)/1L =122,85 g NaCl
