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You wish to make a 0.299 M hydroiodic acid solution from a stock solution of 6.00 M hydroiodic acid. How much concentrated acid must you add to obtain a total volume of 50.0 mL of the dilute solution?

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sebassandin

Answer:

[tex]V_1=2.49mL[/tex]

Explanation:

Hello,

In this case, considering that the moles of hydrioiodic acid remain unchanged during the dilution process:

[tex]n_{HI}=n_{HI}[/tex]

One could apply the following equality in terms of molarity:

[tex]V_1M_1=V_2M_2[/tex]

Whereas the subscript 1 accounts for the solution before the dilution and 2 after the dilution, therefore, the required volume of 6.00 M acid is:

[tex]V_1=\frac{V_2M_2}{M_1} =\frac{50.0mL*0.299M}{6.00M}=2.49mL[/tex]

Best regards.

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