Answer:
x² + y² - 2x + 4y - 11 = 0
Step-by-step explanation:
Given : (x - 1)² + (y + 2)² = 16
So,
(x - 1)² = (x-1) (x-1) = x(x-1) - 1*(x-1) = x² - x - x + 1 = x² - 2x + 1
(y + 2)² = (y+2) (y+2) = y(y+2) + 2(y+2) = y² + 2y + 2y + 4 = y² + 4y + 4
∴ (x - 1)² + (y + 2)² = 16
x² - 2x + 1 + y² + 4y + 4 = 16
x² + y² - 2x + 4y + 1 + 4 - 16 = 0
x² + y² - 2x + 4y - 11 = 0
So, The General form ⇒ x² + y² - 2x + 4y - 11 = 0
