santoshpudasaini61 santoshpudasaini61
  • 21-02-2020
  • Mathematics
contestada

In triangle POR, PO = 9cm and PR = 12cm. If
the area of triangle POR is
[tex]23 \sqrt{3} [/tex]
sqcm, then find
the value of triangle RPO.​

Respuesta :

ujjwal58
ujjwal58 ujjwal58
  • 21-02-2020

Answer:

Area of trangle = 1÷2 (9×12×sinRpo)

23= 1÷2 (108×sinRPO)

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