Answer:
661 btu/lbm, 698 btu/lbm
Explanation:
solution:
First the total specific volume of the mixture is determined from the mass and volume:
α=V/m
=2 ft^3/lbm
Next, the quality of the mixture is obtained from the specific volumes of the constituents at the given pressure using data from:
q=(α-α_liq100)/
(α_vap-α_liq)100
=(2-0.01774)/(4.432-0.01774)
=0.449
Now the enthalpy and internal energy are determined from the quality:
u=u_liq100+qu_evap100
=661 btu/lbm
h=h_liq100+qh_evap100
=698 btu/lbm
