Answer:
1, B
Step-by-step explanation:
When bases are same powers are to be added
=x^(1-2)/x^(-1+0)
=x^(-1)/x^(-1)
=1
[tex] \\ \frac{x. {x}^{ - 2} }{ {x}^{ - 1}. {x}^{0} } = \frac{{x}^{ - 2 + 1} }{ {x}^{ - 1}.1 } = \frac{{x}^{ - 1} }{ {x}^{ - 1} } = 1[/tex]
