Answer:
5.62 m/s
Explanation:
Newton's law of motion can be used to determine the maximum speed of the elevator. In the question, we are given:
Force exerted by the elevator (R) = 1.7 times the weight of the passenger (m*g)
Thus: R = 1.7*m*g
Distance (s) = 2.3 m
Newton's second law of motion: R - m*g = m*a
1.7*m*g - m*g = m*a
a = 0.7*m*g/m = 0.7*g = 0.7*9.8 = 6.86 m/s²
To determine the maximum speed:
[tex]v^{2} _{f} = v^{2} _{i} + 2as[/tex][tex]= 0 + 2(6.86)(2.3) = 31.556[/tex]
[tex]v_{f} = \sqrt{31.556} = 5.62 m/s[/tex]
Therefore, the elevator maximum speed is equivalent to 5.62 m/s.
