Answer:
The correct option is D) .45
Explanation:
The results can be deduced by using the HARDY-WEINBERG LAW.
49% (Since blue is recessive, and the frequency of blue eyes in a population = q squared = .20, the frequency of the blue allele is the square root of q squared = the square root of .20 = .45. Therefore, p, the frequency of the brown allele is 1.0 - .45 = .55. The frequency of the heterozygous population is 2pq = 2 X .45 X .55 which is equal to .49.
