A school is designing two rectangular parking lots. The second parking lot is being designed so that its perimeter is 3/4 of perimeter of the first parking lot. Determine the Perimeter of the second parking lot.

A school is designing two rectangular parking lots The second parking lot is being designed so that its perimeter is 34 of perimeter of the first parking lot De class=

Respuesta :

The perimeter of second plot is 180 feet

Solution:

Given that,

The second parking lot is being designed so that its perimeter is 3/4 of perimeter of the first parking lot

Find the perimeter of first plot:

Perimeter = 2(length + width)

From given figure in question,

length = 40 feet

width = 80 feet

Therefore,

Perimeter = 2(40 + 80)

Perimeter = 2(120) = 240

Thus, we got,

Perimeter of first parking plot = 240 feet

Also, given that,

[tex]\text{Perimeter of second plot }= \frac{3}{4} \times \text{Perimeter of first parking plot}\\\\\text{Perimeter of second plot }= \frac{3}{4} \times 240\\\\\text{Perimeter of second plot }= 180[/tex]

Thus perimeter of second plot is 180 feet