A school is designing two rectangular parking lots. The second parking lot is being designed so that its perimeter is 3/4 of perimeter of the first parking lot. Determine the Perimeter of the second parking lot.
The perimeter of second plot is 180 feet
Solution:
Given that,
The second parking lot is being designed so that its perimeter is 3/4 of perimeter of the first parking lot
Perimeter = 2(length + width)
From given figure in question,
length = 40 feet
width = 80 feet
Therefore,
Perimeter = 2(40 + 80)
Perimeter = 2(120) = 240
Thus, we got,
Perimeter of first parking plot = 240 feet
Also, given that,
[tex]\text{Perimeter of second plot }= \frac{3}{4} \times \text{Perimeter of first parking plot}\\\\\text{Perimeter of second plot }= \frac{3}{4} \times 240\\\\\text{Perimeter of second plot }= 180[/tex]
Thus perimeter of second plot is 180 feet