Answer:
π
Step-by-step explanation:
The integral decomposes into the sum ...
[tex]\displaystyle\int_{-2}^2{\left(x^3\cos{\dfrac{x}{2}}\right)\sqrt{4-x^2}}\, dx+\dfrac{1}{2}\int_{-2}^2{\sqrt{4-x^2}}\, dx[/tex]
The first term of this sum is the integral of an odd function, so is zero. The second term of this sum is 1/2 the area under a semicircle of radius 2, so is ...
A = (1/2)(1/2)π·2² = π
The value of the integral is π.
