Answer:
0.058 g of Al₂O₃
Explanation:
Al₂O₃ → Aluminum oxide
The molar mass is 101.96 g/mol. Therefore 1 mol (NA molecules) are contained in 101.96 grams
NA = Avogadro's number → 6.02×10²³
We make a rule of three to determine the grams we were asked for.
6.02×10²³ molecules are contained in 101.96 g
3.45×10²⁰ molecules will be contained in (3.45×10²⁰ . 101.96 g ) / NA = 0.058 g
