Answer:
[tex]m\angle 1=22^o[/tex]
Step-by-step explanation:
we know that
In a rhombus, opposite angles are congruent, and consecutive angles are supplementary. The diagonals of a rhombus bisect each other.
so
In this problem
[tex]m\angle 1=m\angle 2=m\angle 3=m\angle 4[/tex]
so
[tex]136^o+2m\angle 1=180^o[/tex] ---> by consecutive interior angles
[tex]2m\angle 1=180^o-136^o[/tex]
[tex]m\angle 1=22^o[/tex]
