Answer:
[tex]\sigma=127.32\ pounds/in^2[/tex]
Explanation:
Given that
Load ,P = 100 Pounds
Diameter ,d= 1 inch
We know that stress in the rod due to load P is given as
[tex]\sigma=\dfrac{P}{A}[/tex]
P=Load
A=Area
Now by putting the values in the above equation, we get
[tex]\sigma=\dfrac{100}{\frac{\pi}{4}\times 1^2}\ Pounds/in^2[/tex]
[tex]\sigma=127.32\ pounds/in^2[/tex]
