Answer:
The volume is 214, 3 ml
Explanation:
We calculate the weight of 1 mol of NH4OH:
Weight 1 mol NH4OH= Weight N + (Weight H) * 5 + Weight 0
Weight 1 mol NH4OH= 14g + 1 g* 5 + 16g = 35 g/mol
1 mol NH4OH-----35 g
0,6mol NH4OH----X=(0,6mol NH4OHx 35 g)/1 mol NH4OH= 21 g
We have 0,6 mol in 1000ml of solution (0,600 M)
21g NH4OH-----------1000ml
4,50 g NH4OH------x= (4,50 g NH4OH x 1000ml)/21 g NH4OH= 214, 2857143 ml
