Answer:
Step-by-step explanation:
Heres the full question and solution:
Find an equation for the plane containing the point (1,2,3) and parallel to the plane x+2y+3z=5.
solution
Any plane parallel to [tex]x+2y+3z=5[/tex] is [tex]x+2y+3z=d
[/tex]
since the plane is passing through [tex](1,2,3)[/tex]
we substitute point in equation
[tex]1+2\times 2+3\times 3=d\\d=14
\\x+2y+3z=14[/tex]
equation of the line is [tex]x+2y+3z=14[/tex]
