Answer:
0.4 mL is the volume of 122 g of Cupper (II) nitrate
Explanation:
You have to work with density, to solve the problem.
Density is the relation mass / volume
Cupper (II) nitrate density = Cupper (II) nitrate mass / Cupper (II) nitrate volume
3.05 g/mL = 122 g / Cupper (II) nitrate volume
Cupper (II) nitrate volume = 122 g / 3.05 g/mL
Cupper (II) nitrate volume = 0.4 mL
