Answer:
No, It is not continuous
Step-by-step explanation:
The function [tex]f(x)=\frac{1}{x}[/tex] will be continuous on the open interval (-4,4) if there is no vertical asymptote or hole on (-4,4).
But the given function has a vertical asymptote at [tex]x=0[/tex].
Therefore [tex]f(x)=\frac{1}{x}[/tex] is not continuous on the interval (-4,4) because x=0 belongs to the given interval.
