Answer: Eight (8) different kinds of gametes can be produced by an individual with the genotype AABbCCddEeFf.
Explanation: Total number of gametes that can be formed can be determined by the formula 2^n where n is the number of heterozygous loci.
The heterozygous loci in the genotype AABbCCddEeFf are Bb Ee and Ff; n = 3
Therefore, 2^n = 2^3 = 2 x 2 x 2 = 8.
