Answer:
the distance is d= 11/3
Step-by-step explanation:
considering the point P=( 0,9,0) and the plane F(x,y,z)=ax+by+cz+d=x+4y+8z -3 =0 ,
then the distance d is
d = | P evaluated in F | / √(a²+b²+c²)
d = | 0*1 + 4*9 + 8*0 - 3 | / √(1²+4²+8²) = 33/9 = 11/3
