Answer:
18 V
Explanation:
The 3Ω resistor and the 6Ω resistor are in parallel, so the voltage difference across them is equal.
V = IR
V = (2 A) (3 Ω)
V = 6 V
So the current going through the 6Ω resistor is:
V = IR
6 V = I (6 Ω)
I = 1 A
Therefore, the current going through the 4Ω resistor is the sum:
I = 2 A + 1 A
I = 3 A
The voltage drop across the 4Ω resistor is:
V = IR
V = (3 A) (4 Ω)
V = 12 V
So the total voltage difference between K and L is:
V = 6 V + 12 V
V = 18 V
