Step by step explanation:
9[tex]x^{2}[/tex]+6x+5=0
Uses the "a", "b", and "c" from "a[tex]x^{2}[/tex] + bx + c", where "a", "b", and "c" are numbers
So in this case:
a would be 9
b would be 6
c would be 5
Then plug in from there..
Another way you can do it is using the square method.
