Answer:
[tex]f(g(x))=\frac{x-1}{10-3x}[/tex]
Step-by-step explanation:
[tex]f(x)=\frac{1}{x-3}\\\\g(x)=\frac{9}{x-1}\\\\f(g(x))=f(\frac{9}{x-1})\\\\f(g(x))=\frac{1}{g(x)-3}\\\\f(g(x))=\frac{1}{\frac{9}{x-1}-3}=\frac{x-1}{9-3(x-1)}=\frac{x-1}{10-3x}[/tex]
