An important information or constant to recall here is the Avogadros constant. This will help us solve how many moles are there from the number of atoms given. These is how we proceed: [tex]1.773x10^ {17}* \frac{ mol}{6.02*10^{23}} * \frac{1 mole Na2CO3}{1 moleC}* \frac{105.98g Na2CO3}{mol} = 3.12 * 10^{-5} [/tex]
Answer: 3.12 * 10^{-5} grams of Sodium carbonate (Na2CO3)
