Answer:
tan(A) = √3
Step-by-step explanation:
In the third quadrant, the tangent is positive. For sin(A) = -√(3/4), the tangent is ...
[tex]\tan{A}=\dfrac{\sin{A}}{\cos{A}}=\dfrac{-\sqrt{\dfrac{3}{4}}}{-\sqrt{1-\left(\sqrt{\dfrac{3}{4}}\right)^2}}=\sqrt{\dfrac{\left(\dfrac{3}{4}\right)}{\left(\dfrac{1}{4}\right)}}\\\\\tan{A}=\sqrt{3}[/tex]
