Answer:
C
Step-by-step explanation:
assuming point (0,0) is D
let assume mid point of line DA is E
so x and y coordinate of point E
(x , y) = ( (4m+0)/2, (4n +0)/2 )
(x, y ) = ( 2m, 2n)
let assume F is the midpoint of line BC
so coordinates of point F is
(x , y) = ( (4q+4p)/2 , (4n+0)/2 )
(x , y ) = (2q+2p, 2n)
so now the coordinate or midpoint of mid segment EF is
(x , y) = ( (2m+2q+2p)/2, (2n+2n)/2 )
(x , y) = (m+q+p, 2n)
