Answer:
C. 0, 1.29, -0.65
Step-by-step explanation:
The real solutions of the equation [tex]19x^3-12x^2-16x=0[/tex] is where the graph of [tex]y=19x^3-12x^2-16x[/tex] intersects the x-axis.
This means that we need to graph [tex]y=19x^3-12x^2-16x[/tex] using a graphing software.
From the graph shown in the attachment [tex]x=0[/tex], [tex]x=1.29[/tex], and [tex]x=-0.65[/tex] are the real solutions.
The correct choice is C
