Respuesta :

sqdancefan

Answer:

  9z

Step-by-step explanation:

The relevant rules of exponents are ...

  [tex]\sqrt[n]{z}=z^{\frac{1}{n}}\\\\(z^a)(z^b)=z^{a+b}[/tex]

So you have ...

  3·z^(1/4)·3·z^(3/4) = 3·3·z^(1/4+3/4) = 9z^(4/4) = 9z

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