Answer:
-\left(\dfrac{1}{2}y+\dfrac{1}{4}\right)=-\dfrac{1}{2}y-\dfrac{1}{4}=-\dfrac{1\cdot2}{2\cdot2}y-\dfrac{1}{4}=\dfrac{-2y}{4}-\dfrac{1}{4}=\dfrac{-2y-1}{4}\\\\=-\dfrac{2y+1}{4}
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