You are designing a rectangular enclosure with 2 rectangular sections separated by parallel walls. The interior wall has a length of 30 feet and the area of the enclosure is 1800 ft2. What amount of fencing is required for this project?

Respuesta :

Answer:

[tex] P = 3L + 4W= 3*30 ft + 4*30 ft = 210 ft[/tex]

So then is required at least 210 ft in order to satisfy the conditions.

Step-by-step explanation:

For this case we can assume that the rectangular enclosure is on the figure attached.

The perimeter on this case is given by:

[tex]P = 3L + 4W[/tex]

We know that the total area is [tex] 1800ft^2[/tex] and the total area is given this formula:

[tex] A= 2L W[/tex]

Because we have two identical rectangular pieces.

And we can find the value for W like this:

[tex] W = \frac{A}{2L} =\frac{1800 ft^2}{2*30 ft}= 30ft[/tex]

And then we can find the perimeter like this:

[tex] P = 3L + 4W= 3*30 ft + 4*30 ft = 210 ft[/tex]

So then is required at least 210 ft in order to satisfy the conditions.