Answer: 0.0416 moles BaCl2 or 4.16x10-2 moles BaCl2
Explanation: solution just multiply the given value 8.62g x 1mol BaCl2/207g which is the molar mass of barium chloride.
Answer: 0.04137 moles
Explanation:
Ba = 137.327amu
Cl = 35.5
BaCl2 = 137.327 + (35.5*2)
BaCl2 = 137.327 + 71
BaCl2 = 208.327amu
1 mole of BaCl2 contains 208.327 g
x mole is present in 8.62g of BaCl2
x = 8.62 * 1 / 208.327
x = 0.04137g
