Respuesta :

Kuku861
I get a list of zeroes: x = ±1, –3, 2 ... For instance, for x = 2 to be a solution, then I must have solved the factor equation x – 2 = 0, which means that x – 2 must have been a ... Find the quadratic with zeroes at x = 3/2 and x = –5/4
jhonyy9
x^2 +3x -4 = 
x*x -x +4x -4 =
x(x-1) +4(x-1)=
(x+4)(x-1)

so the 3rd choice is right sure