coopergang coopergang

16-06-2016
Mathematics

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consider the equation 3tan^2(x)−1=0.
the solutions of this equation over the interval {0,pi} are?

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janmejaysinha4 janmejaysinha4

16-06-2016

3tan^2(x)-1=0
=> 3tan^2(x)=1
=> tan^2(x)=1/3
=> tan(x)= √(1/3) and -√(1/3)
=> x= tan^-1 *(√(1/3)) and tan^-1 *(-√(1/3))

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