Answer:
[tex]y-2=-\frac{4}{3}(x-0)[/tex]
Step-by-step explanation:
we know that
The equation of the line in point slope form is equal to
[tex]y-y1=m(x-x1)[/tex]
we have
[tex]y=-\frac{4}{3}x+2[/tex] ---> equation in slope intercept form
so
Convert to point slope form
subtract 2 both sides
[tex]y-2=-\frac{4}{3}x[/tex]
Rewrite as
[tex]y-2=-\frac{4}{3}(x-0)[/tex]
the slope is [tex]m=-\frac{4}{3}[/tex]
the point is [tex](0,2)[/tex]
