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Given the balanced chemical equation below, how many grams of oxygen, O2, will be produced by the complete decomposition of 225.7 grams of potassium chlorate, KClO3? The molar mass of potassium chlorate, KClO3, is 122.55 gmol, and the molar mass of oxygen gas, O2, is 31.998 gmol.

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Answer:

The complete decomposition will produce 88.4 g of O₂

Explanation:

The balanced chemical equation for this reaction is:

2KClO₃ (s)  →  2KCl (s)  +  3O₂ (g)

So 2 moles of salt, produce 3 moles of gas.

How many moles of chlorate are 22537 g?

Mass / Molar mass = 225.7 g / 122.55 g/m = 1.84 moles

This will be a rule of three:

2 moles of salt produce 3 moles of gas

1.84 moles of salt produce ( 1.84  .3)/2 = 2.76 moles

Moles . molar mass = mass

(To find out the masss of compound produced)

2.76 m  . 31.998 g/m = 88.4 grams

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