Answer:
[tex]W=3\ units[/tex]
Step-by-step explanation:
we have
[tex]V=LWH[/tex] ----> equation A
[tex]W=H[/tex] ---> equation B
substitute equation B in equation A
[tex]V=LW(W)[/tex]
[tex]V=LW^2[/tex] ----> equation C
we have
[tex]V=252\ units^3\\L=28\ units[/tex]
substitute in the equation C
[tex]252=(28)W^2[/tex]
solve for W
[tex]W^2=252/(28)[/tex]
[tex]W^2=9[/tex]
[tex]W=3\ units[/tex]
