Answer:
(1, -3)
Step-by-step explanation:
Solve the system of equations of the two lines:
10x-3y=19 ------> eq 1
5x+4y=-7 --------> eq 2
Solve by elimination:
eq 2 x 2
2( 5x+4y) = 2(-7 )
10x + 8y = - 14 ------> eq 3
eq3 - eq 1:
(10x + 8y) - (10x-3y) = - 14 - 19
10x + 8y - 10x + 3y = -33
8y + 3y = -33
11y = -33
y = -3 (substitute back into eq 1)
10x - 3y = 19
10x - 3(-3) = 19
10x + 9 = 19
10x = 19 - 9
10x = 10
x = 1
Hence the intersection point is (1, -3)
