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AA cash register has only one-dollar bills and five-dollar bills, and no change. There are $6$6 times as many one-dollar bills as five-dollar bills. The total amount in the cash register is $231.

Respuesta :

Answer:

There are 126 $1 bills and 21 $5 bills.

Step-by-step explanation:

Given,

Total cash Amount = $231

Solution,

Let the number of $1 bill be 'x'.

And  the number of $5 bill be 'y'.

Now according to question, one-dollar bills is six times of five-dollar bills.

So, we can frame it in equation form as;

[tex]x=6y[/tex]   ⇒ equation 1

Again according to question, there is only one-dollar bills and five-dollar bills, and no change.

That means the total cash amount is in the form of $1 and $5.

So, we can frame the above sentence in equation form as;

[tex]1\times x+5\times y=231\\\\x+5y=231[/tex]⇒ equation 2

Now substituting the value of x in equation 2, we get;

[tex]6y+5y=231\\\\11y=231\\\\y=\frac{231}{11}=21[/tex]

So, [tex]x=6y=6\times 21=126[/tex]

Hence There are 126 $1 bills and 21 $5 bills.

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