Answer:
B) [tex]R= \sqrt{(40N)^2+(30N)^2}[/tex]
Explanation:
Given [tex]\sum Fx=40N\ \ \ \ \ \ \ \ \ \sum Fy=30N[/tex]
As the forces are on X and Y-axis. We can see the angle between the forces is 90°
Using vector addition formula. Since the angle between the forces is 90°
[tex]R=\sqrt{\sum (Fx)^2+\sum (Fy)^2}[/tex]
[tex]R= \sqrt{(40N)^2+(30N)^2}[/tex]
Please see the attachment.
