kyleight2006
kyleight2006 kyleight2006
  • 20-11-2019
  • Mathematics
contestada

Find the lengths of DE and EF. Note: Segments BC and DF are parallel.

Find the lengths of DE and EF Note Segments BC and DF are parallel class=

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kudzordzifrancis
kudzordzifrancis kudzordzifrancis
  • 24-11-2019

Answer:

DE=9

FE=15

Step-by-step explanation:

Triangle EBC is similar to triangle EDF.

Therefore

[tex] \frac{DE}{DB}= \frac{FE}{CE}[/tex]

[tex] \frac{5x - 4 + 3}{3} = \frac{4x + 2 + 5}{5} [/tex]

[tex] \frac{5x - 1}{3} = \frac{4x + 7}{5} [/tex]

[tex]5(5x - 1) = 3(4x + 7)[/tex]

Expand to get;

[tex]25x - 5 = 12x + 21[/tex]

Group similar terms:

[tex]25x - 12x = 21 + 5[/tex]

[tex]13x = 26[/tex]

Divide both sides by 13 to get:

[tex]x = 2[/tex]

We substitute to get:

DE= 5x-3+4

DE=5*2-3+4

DE=10-1=9

Also,

FE=4x+2+5

FE =4*2+2+5

FE=8+7

FE=15

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