35a. We're asked to compute the ratio between the enlarged width and the original width. So we literally perform the operation:
[tex]6.5\div 3.5 \approx 1.86[/tex]
35b. If the order is wrong the image would be shrunk instead of enlarged, with a ratio of [tex]3.5\div 6.5[/tex]
36. We know that
[tex]\dfrac{p}{q}=\dfrac{2}{3}[/tex]
Observe that
[tex]\dfrac{6p}{2q}=\dfrac{6}{2}\cdot\dfrac{p}{q}=3\cdot\dfrac{p}{q}=3\cdot\dfrac{3}{2}=\dfrac{9}{2}[/tex]
