Answer:
the numbers are 4 and 12
Step-by-step explanation:
Given that
x + y = 16 ---------------- eq1
x^2 + y^2 = 160 -------- eq2
From eq1:
x = 16-y
Putting in eq2
(16 - y)^2 + y^2 -160 = 0
256 -32y + y^2 +y^2 - 160 = 0
96 -32y +2y^2 = 0
Taking 2 common:
48 - 16y + y^2 = 0
48 - 12y - 4y +y^2 = 0
12(4 - y) -y(4 - y)= 0
(12 -y) (4 - y) = 0
So weather:
y=4
OR
y = 12
Now put vaules of y in eq1
x + 4 = 16 =====> x = 12
x + 12 = 16=====> x = 4
So the numbers are 4 and 12
i hope it will help YOU!
