Answer:
y=-1(x-6)^2+32
Step-by-step explanation:
vertex form: y=a(x-h) ^2+k
you have your equation in standard form : ax^2+bx+c
how to change it:
vertex x=(-b)/2(a)
x=-(12)/2(-1)
x=6
substitute x into original (standard-form) equation to find y
vertex y=-(6)^2+12(6)-4
y=32
substitute those values into your vertex (h,k) : (6,32)
y=-1(x-6)^2+32
hope this helps!! :)
