Answer:
[tex]2.8\times 10^2\ rpm[/tex]
Explanation:
B = Magnetic field = 1.1 T
L = Length of square = 10.4 cm
A = Area of square = [tex]L^2[/tex]
t = Time taken
V = Voltage = 120 V
N = Number of turns = 350
[tex]\omega[/tex] = Angular frequency
Voltage in the generator is given by
[tex]V=NAB\omega sin\omega t[/tex]
Voltage is maximum when [tex]sin\omega t=1[/tex]
[tex]V=NAB\omega\\\Rightarrow \omega=\frac{V}{NAB}\\\Rightarrow \omega=\frac{120}{350\times 0.104^2\times 1.1}\\\Rightarrow \omega=28.81733\ rad/s=\frac{28.81733}{2\pi}\times 60=275.18\ rpm[/tex]
The minimum rotation rate of the coil so it will produce the required voltage is [tex]2.8\times 10^2\ rpm[/tex]