Answer:
Sin(60°)=[tex]\frac{\sqrt{3} }{2}[/tex]
Explanation:
Assuming the given angles are in degrees
We know that Sin(A-B)=SinACosB-CosASinB
Here A=100° and B=40°
[tex]Sin(100)Cos(40)-Cos(100)Sin(40)=Sin(100-40)=Sin(60)=\frac{\sqrt{3} }{2}[/tex]
