In designing circular rides for amusement parks, mechanical engineers must consider how small variations in certain parameters can alter the net force on a passenger. Consider a passenger of mass m riding around a horizontal circle of radius rat speed v. What is the variation dF in the net force magnitude for(a) a variation dr in the radius with ν held constant,(b) a variation dv in the speed with r held constant, and(c) a variation dT in the period with r held constant?

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aristocles aristocles · Answer 1 · 2019-11-21T02:44:56+01:00

Answer:

Part a)

[tex]dF = -\frac{mv^2}{r^2} dr[/tex]

Part b)

[tex]dF = \frac{2mvdv}{r}[/tex]

Part c)

[tex]dT = - \frac{2\pi r}{v^2} dv[/tex]

Explanation:

Part a)

As we know that force on the passenger while moving in circle is given as

[tex]F = \frac{mv^2}{r}[/tex]

now variation in force is given as

[tex]dF = -\frac{mv^2}{r^2} dr[/tex]

here speed is constant

Part b)

Now if the variation in force is required such that r is constant then we will have

[tex]F = \frac{mv^2}{r}[/tex]

so we have

[tex]dF = \frac{2mvdv}{r}[/tex]

Part c)

As we know that time period of the circular motion is given as

[tex]T = \frac{2\pi r}{v}[/tex]

so here if radius is constant then variation in time period is given as

[tex]dT = - \frac{2\pi r}{v^2} dv[/tex]