Answer:
x = 0, y = 2
Step-by-step explanation:
Given:
[tex]y =-\frac{1}{3}x+2[/tex]⇒ Equation 1
[tex]y = x+2\\[/tex]
Now Substituting value of [tex]y= x+2[/tex] in equation 1 we get
[tex]x+2= -\frac{1}{3}x+2\\x+\frac{1}{3}x=2-2\\[/tex]
[tex]\frac {3x+x}{3}=0\\4x=0\\x=0[/tex]
Substituting value of x in equation [tex]y=x+2[/tex] we get
[tex]y= 0+2\\y=2[/tex]
