Answer:
V₂ = 9.02 L
Explanation:
Given data:
Initial volume = 4.51 L
Initial temperature = 0°C ( 273 k)
Final temperature = 273 °C (273+273 = 546 K)
Final volume = ?
Solution:
V₁/T₁ = V₂/T₂
V₂ = V₁T₂/T₁
V₂ = 4.51 L×546 K / 273 k
V₂ = 2462.46 L /273
V₂ = 9.02 L
