[tex](22 \sqrt{2}) \div 2[/tex]
22 root 2 over 2 centimeters
Step-by-step explanation:
since it's a 45 45 90 triangle, the side lengths are x, and the hypotenuse is x square root 2. So, if the hypotenuse is 22, you divide the hypotenuse by square root 2, rationalize the denominator(multiply numerator and denominator by square root 2), and then you get 22 root 2 over 2
