Answer:
54 N
Explanation:
We have two positive charges 12uC and 5 uC ,they are kept at a distance of 10cm.
We have a relation for force between two charges q1,q2 as
[tex]F=\frac{kq1q2}{r^{2} }[/tex]
Value of k is [tex]9*10^9[/tex]
On substituting the values into the equation we get,
[tex]F=\frac{9*10^9*12*5}{10^9*10}\\\\ F=54N[/tex]
Hence the force between them is 54 N.
