Respuesta :

alise47
Let 6x-3y=3 be equation 1 and -2x +6y=14 be equation 2.

Take 2 common from eq 2 let the optioned eq be equation number 3.

And solve eq number 1 and 3.
Goldenbabiy

Answer:

Solving the system of equations using elimination involves eliminating one variable by adding or subtracting the equations. Elimination method is as follows:

5)2x + 6y = -12)

2(5x - 5y = 10

10x - 30y = -60

10x - 10y = 20

We subtract the equations eliminating the 10x term.

40y = -80

y = -2

x = (10 + (-2)5) / 5

x=0

Hope this helps!

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